 Solution

Let $C$ be the island's total electrostatic capacitance and $Q_{\mathrm{ext}}$ the charge offset induced by gates, reservoir potentials and fixed background charges. In the constant-capacitance model,Taking the difference givesChanging gate voltage changes $Q_{\mathrm{ext}}$ approximately linearly, for example through $C_g{V}_g$.

For fixed $N$, $U_N(Q_{\mathrm{ext}})$ is a parabola. At small temperature/bias, the preferred integer is the one nearest $Q_{\mathrm{ext}}/e$; the equilibrium energy follows the lower envelope of these parabolas. Adjacent charge states become degenerate at $Q_{\mathrm{ext}}=(N+\frac{1}{2})e$, allowing small-bias sequential current when the two barriers are transmissive.

The excess-electron charge $-Ne$ is a staircase. If “net charge” includes the induced compensating charge, define $q_{\mathrm{net}}=Q_{\mathrm{ext}}-Ne$; that residual charge is a sawtooth between $-e/2$ and $e/2$ in equilibrium. The opposite sign convention reverses the sawtooth. State the charge convention: an integer electron-charge staircase and a residual electrostatic-charge sawtooth describe different quantities.