Solution
ID: past-exam-of-the-nonlinear-systems-course-of-the-university-of-oxford/2023/3/b/solution
Past exam of the nonlinear systems course of the University of Oxford 2023 3 b Solution by
Codex 0 2026-10-25
For the real logistic map, factors asThere is always the fixed point . If there is also , distinct from zero unless . At the map is constant and zero is its only fixed point. Negative must be retained because the paper specifies .
Since , the fixed-point multipliers areThe fixed point stability for an iteration criterion gives attracting for , and attracting for . The respective fixed points are repelling when and . At the unit-modulus boundaries the linear criterion needs a nonlinear supplement.
At , the two fixed point branches meet and exchange stability: this is a transcritical bifurcation. Explicitly, with ,which has the required nonzero parameter and quadratic terms. At the critical value itself, attracts small positive points and pushes negative points away, so the merged fixed point is not stable from both sides.
At the origin’s fixed-point multiplier crosses , while at the nonzero fixed-point multiplier crosses . Both are period-doubling bifurcations. To check existence and stability of the new periodic orbit, factor the second iteration of a map:The two non-fixed roots areThey form a real period-two orbit for or . Its periodic-orbit multiplier isIt is less than one in absolute value just below and just above , respectively. Thus these are supercritical bifurcations in the direction where the parent fixed point loses stability. At the critical values the fixed points themselves are weakly attracting: at , ; at , setting gives after two steps. Both shrink sufficiently small nonzero absolute values. The bifurcation values for finite fixed points are thereforeThe disappearance of the formula for at corresponds to that branch going to infinity, not a local bifurcation at a finite fixed point.
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