 Solution

ID: past-exam-of-the-options-i-course-of-the-university-of-oxford/2013/m/1/a/solution

t

, with mean equal to rate times length. Fifteen minutes is

1/4

hour, so

N (5 : 15) - N (5 : 00) \sim Poisson (3), P (N = k) = e^{- 3} \frac{3 ^{k}}{k !}, k \geq 0.

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