Solution
ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2012/f/f2/c/i/solution
Past exam of the options II course of the University of Oxford 2012 F F2 c i Solution by
Codex 0 2026-10-31
The chain rule givesIts determinant is , so it is invertible. The map is smooth and . The inverse function theorem therefore yields an open neighbourhood of the origin for which is open, contains the origin, and
New to topics? Read the docs here!