Solution

ID: past-exam-of-the-partial-differential-equations-for-pure-and-applied-mathematicians-and-calculus-of-variations-course-of-the-university-of-oxford/2007/a/4/solution

The spectral theorem for compact self-adjoint operators used here concerns a compact self-adjoint operator: its nonzero eigenvalues are real, have finite multiplicity and can accumulate only at zero; the orthogonal complement of its kernel is the closed span of its orthonormal eigenvectors. Self-adjointness is essential for this eigenbasis statement.
Let be the unique zero-parameter weak solution. Uniqueness gives linearity. Testing with and using coercivity gives . The Rellich-Kondrachov theorem makes the embedding compact on this bounded domain, so is compact on . Symmetry gives
It is self-adjoint and positive. It is injective: if , the weak equation pairs to zero with all tests, dense in , so . Moreover for .
The parameter equation is equivalent to , that is
A solution of this operator equation in lies in , because its right-side representation is , and the equivalence follows in both directions. For , the form remains coercive; the preceding minimization argument gives a unique weak solution.
The spectral theorem now supplies a complete orthonormal basis of with , , and . The elliptic eigenvalues are , with finite multiplicity and tending to infinity, and weakly. If is not one of them, then
This converges even in : its squared energy norm is , finite because the multiplier is bounded over . Partial sums solve the weak equation with the corresponding projections of . Passing to the limit proves the equation for every test; the same coefficients force uniqueness. Thus the expansion represents the unique weak solution away from the elliptic eigenvalues.

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