 Solution

For gamma decay, the nuclear gamma-ray multipole selection rules require the radiation's angular momentum $L$ to satisfy the triangle inequalityHere $J_i=J_f=5/2$, so $0\le L\le 5$. A real emitted photon has no monopole radiation mode, leaving $L=1,2,3,4,5$.

The two nuclear quantum states have the same parity. An electric multipole has parity factor $(-1{)}^L$, while a magnetic multipole has factor $(-1{)}^{L+1}$. Thus electric radiation requires even $L$ and magnetic radiation odd $L$:In particular, an $E0$ nuclear transition cannot emit the single real photon requested here; processes such as internal conversion are different decay channels.

For usual nuclear gamma ray energies, $kR\ll 1$, where $k=E_{\gamma }/(\hslash c)$ and $R$ is the nuclear size. Higher multipole radiation orders bring extra powers of this small parameter, so $M1$ and $E2$ are the likely important contributions, with $M3$, $E4$ and $M5$ generally much smaller. Often $M1$ is dominant, but an allowed $M1$ matrix element can be hindered and an $E2$ transition can be collectively enhanced. The quantum numbers alone do not fix a numerical relative contribution or an unconditional ordering of the $M1$ and $E2$ rates.