 Solution

Scientific confirmation is evidential support rather than deductive proof. Two distinct problems concern, first, what counts as relevant positive evidence and, second, which part of a tested theoretical package that evidence supports. A defensible response makes background information and the production of evidence explicit. The following two problems are independent: resolving the logical puzzle about positive instances does not eliminate ambiguity about auxiliary hypotheses.

Problem one: the raven paradox. Write the hypothesis aswhere $R$ means “is a raven” and $B$ “is black”. Its contrapositive isThe hypotheses are logically equivalent. A plausible equivalence principle says that identical information must support them equally. A plausible instance principle says that an observed $F$ that is $G$ confirms “every $F$ is $G$”. Combining the principles makes a nonblack nonraven, such as a white shoe, support the raven hypothesis. That conflicts with the intuition that inspecting shoes tells us nothing about ravens. Hempel develops the puzzle in his analysis of instance-based scientific confirmation.^[ref]

My preferred response retains logical equivalence while rejecting an unconditional instance rule. By Bayes' theorem, for evidence $E$, background $K$ and positive relevant probabilities,An instance's bearing depends on how likely it was under the competing possibilities, including how the object was selected. No rule depending only on the grammatical form of an instance can settle that comparison. Branden Fitelson and James Hawthorne analyse the role of background assumptions and Bayesian confirmation in this puzzle.^[ref]

Here is an explicit illustrative model. There are 100 labelled objects: ten known ravens and ninety known nonravens. Under $H$ all ten ravens are black; under the sole alternative $A$, exactly one of the ten is nonblack, with its identity uniformly distributed. Nonraven colours are already known and identical under both possibilities, and the prior probabilities of $H,A$ are equal. Selecting a known white shoe according to a rule independent of $H,A$ has the same likelihood under each, so the posterior probability of $H$ stays $1/2$. A uniformly selected raven, however, is black with probability $1$ under $H$ and $9/10$ under $A$. After observing it to be black,If sampling is instead from known nonblack objects whose membership is uncertain, discovering a nonraven can rule out a possible counterexample and provide support. There is no context-independent prohibition on support from a nonraven. The response explains both the familiar irrelevance intuition and why it is not universally correct. Its limit is that the prior probabilities and sampling assumptions need independent defence; the calculation is a transparent model, not a theorem that all shoes are irrelevant.

Problem two: the Duhem problem of testing a package. Suppose the target hypothesis $T$ and auxiliary hypotheses $A$ jointly imply an outcome $E$:A failure gives $\neg (T\wedge A)$, equivalently $\neg T\vee \neg A$, rather than $\neg T$ alone. Success also does not establish either premise: that would affirm the consequent. Pierre Duhem's point is especially pressing for physical experiments whose predictions require theories of the apparatus as well as the target system.^[ref]

My preferred response combines independent calibration, deliberately varied tests and explicit comparison of packages. For a simple model, suppose a detector has independently calibrated false-positive probability $f$ and detection efficiency $d$. A target predicts a signal on each trial with probability $s$. Then the positive-output probability isUnder a no-signal rival it is $p_0=f$. If $s=1/2$, $d=9/10$, and $f=1/10$, then $p_T=1/2$. One positive reading supplies a Bayes factor of $5$ for the specified target package against the specified no-signal package. But an uncalibrated faulty detector with false-positive probability $1/2$ fits the same positive-reading rate. Target data alone do not distinguish those packages.

Signal-absent calibration trials test the false-positive assumption directly. If ten independent such trials are all negative, their likelihood ratio in favour of $f=1/10$ against $f=1/2$ isThis does not magically isolate $T$: the calibration relies on its own assumptions, and correlated trials would invalidate the power calculation. It shows concretely how additional evidence can discriminate explanations that the initial data leave unresolved. Repeating the target measurement with apparatus based on different physical processes further reduces dependence on one shared failure mode.

Thus the Duhem problem defeats automatic attribution of support or failure, not rational experimental comparison. Where rivals remain empirically equivalent, suspension of judgement about their difference is appropriate. Together, the two responses defend scientific confirmation as a structured, fallible comparison using background information, rather than either pure instance counting or a mechanical verdict on an isolated hypothesis.