 Solution

Plot position $x$ horizontally and $ct$ vertically, with equal length scales, so vacuum light rays have slopes $\pm 1$. A possible cause of the spacetime event $A$ must lie on or inside its past light cone, with $\Delta t=t_A-t_{\mathrm{cause}}>0$. Equivalently, causality requires $|\Delta x|\le c\Delta t$.

From $B$ to $A$, $\Delta x=6\mathrm{m}$ and $\Delta t=10^{-8}\mathrm{s}$. Using $c\simeq 3.00\times 10^8\mathrm{m}{\mathrm{s}}^{-1}$, the available light-travel distance is only $c\Delta t=3.00\mathrm{m}$. In the $(-,+,+,+)$ metric signature, the Minkowski interval isThere is spacelike separation, so a signal would need speed $6\times 10^8\mathrm{m}{\mathrm{s}}^{-1}\simeq 2c$:From $C$ to $A$, $\Delta x=-2\mathrm{m}$ and $\Delta t=1.5\times 10^{-8}\mathrm{s}$. Now $c\Delta t=4.50\mathrm{m}>|\Delta x|$, givingThis is timelike separation, with a possible signal velocity $-2/(1.5\times 10^{-8})\simeq -1.33\times 10^8\mathrm{m}{\mathrm{s}}^{-1}$. Therefore