 Solution

ID: past-exam-of-the-physics-2-paper-of-the-university-of-oxford/2014/9/iv/solution

Only the ideal inductor stores energy in this circuit; ideal resistors dissipate energy as heat. With

I_{1} (\infty) = V / (4 R)

U_{stored} = \frac{1}{2} L I_{1} (\infty)^{2} = \frac{L V ^{2}}{32 R ^{2}} .

The question excludes the battery's internal energy, and the continuously generated resistor heat is not stored electromagnetic energy.

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