 Solution

ID: past-exam-of-the-physics-2-paper-of-the-university-of-oxford/2018/9/ii/solution

I_{C} = C d V / d t

, so

Z_{C} = \frac{1}{iω C}, I_{C} (t) = - ω C V_{0} sin ω t = ω C V_{0} cos (ω t + π /2) .

The electric current leads the voltage by $π /2$ .

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