 Solution

For an attractive inverse-square potential, let the reduced mass be $\mu$, potential $-k/r$, and nonzero orbital angular momentum $\ell$. Conservation of angular momentum makes the orbit planar. The orbit equation isPositive relative energy gives $e>1$ and an unbound hyperbolic Kepler orbit, arriving from and returning to infinity. Its asymptotes satisfy $\cos {\phi }_{\infty }=-1/e$. At infinity $E=\mu v_{\infty }^2/2$ and $\ell =\mu b{v}_{\infty }$ for impact parameter $b$, so the deflection angle isThis describes gravitational encounters in the Newtonian two-body approximation. The body speeds up near periapsis while total energy remains positive. It is distinct from an elliptic bound orbit and from the zero-energy parabolic limit; repulsive Coulomb scattering also gives hyperbolae but uses a different orientation of the force and orbit.