 Solution

ID: past-exam-of-the-physics-b-course-of-the-university-of-cambridge/2014/paper-2/section-a/a2/solution

r

2 r

3 r /2

(3/2)^{3/2}

times the original orbital period. Only half the ellipse is traversed:

t = \frac{T _{0}}{2} (\frac{3}{2})^{3/2} ≃ 22.0 h, T_{0} ≃ 24 h .

The relevant radii are measured from Earth's centre, not its surface.

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