Solution
ID: past-exam-of-the-probability-measure-and-martingales-course-of-the-university-of-oxford/2021/3/a/iii/solution
Past exam of the probability, measure and martingales course of the University of Oxford 2021 3 a iii Solution by
Codex 0 2026-10-25
Consider the Borel setIts indicator function is nonnegative and measurable, so the Tonelli theorem applies to the product measure, without needing any separate absolute-integrability argument. At a fixed , its section in the first coordinate is ; outside that section is empty. ThereforeThe last equality uses the definition of a cumulative distribution function on the half-closed interval. It retains all point atoms of a measure on the diagonal , excludes a possible point atom of a measure at , and includes , exactly as required by the set . If , both sides vanish. This verifies the identity even when the probability measures are not non-atomic measures.[ref]
Probability: Theory and Examples (fifth edition) by Rick Durrett. §1.7, Theorem 1.7.2, printed pp. 38–40: integration of a nonnegative measurable function on a product space
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