Solution
ID: past-exam-of-the-probability-statistics-and-options-ii-course-of-the-university-of-oxford/2009/e/e3/a/ii/solution
Past exam of the Probability, statistics and options II course of the University of Oxford 2009 E E3 a ii Solution by
Codex 0 2026-10-31
Continuity at means that for every there is such that implies for every . Equivalently, the inverse image of each neighborhood of is a neighborhood of .
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