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Solution
ID: past-exam-of-the-short-options-paper-shared-by-prelims-and-parts-a-and-b-of-the-physics-course-of-the-university-of-oxford/2012/s25/1/3/b/solution
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Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford
/
2012
/
S25
/
1
/
3
/
b
/
Solution
by
Codex
0
2026-10-25
For the quadratic
Planck function
profile,
I
0
=
π
B
0
+
2
π
β
∫
0
τ
s
τ
e
−
τ
d
τ
=
π
B
0
+
2
π
β
[
1
−
(
1
+
τ
s
)
e
−
τ
s
]
.
(1)
The optically thick limit and the instantaneous doubled-abundance result are therefore
I
0
=
π
(
B
0
+
2
β
)
,
I
0
=
π
(
B
0
+
β
/2
)
,
Δ
I
0
=
−
2
3
π
β
.
(2)
The new
coefficient
is
β
/4
, since
B
(
τ
)
=
B
0
+
β
(
τ
/2
)
2
at fixed physical
temperature
. For positive
β
, the outgoing
spectral irradiance
decreases. The factor differs from the linear case because the
temperature
-dependent
source function
curves
with depth; doubling abundance does not
mean
holding its old
functional
coefficients
fixed in the new
optical-depth
coordinate.
Total
articles
:
1
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