Solution
ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2013/digital-systems-linear-algebra-introduction-to-formal-proof/6/e/solution
Past exam of the year 1 of the computer science course of the University of Oxford 2013 Digital systems, linear algebra, introduction to formal proof 6 e Solution by
Codex 0 2026-10-31
The factor proves that one is an eigenvalue. To find its normalized eigenvector, solve . The second and third rows giveso . The normalization now givesIts entries are nonnegative and sum to one, and direct matrix multiplication verifies . As a probability vector it is the stationary distribution; as resource shares it assigns half to the USA and a quarter to each other region.
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