 Solution

ID: past-exam-of-the-year-1-of-the-computer-science-course-of-the-university-of-oxford/2018/discrete-mathematics-continuous-mathematics-and-probability/4/b/iii/solution

e^{2 s i n x}

2 cos x

. Multiplying the differential equation by it cancels the right-hand exponential and yields

(e^{2 s i n x} y)^{'} = 1

. Hence

y (x) = (x + C) e^{- 2 s i n x}, C \in R .

This formula is actually defined for every real

x

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