 Solution

ID: past-exam-of-the-year-2-of-the-earth-sciences-geology-course-of-the-university-of-oxford/2022/paper-1/7/a/solution

For pure phases at the

1

bar reference pressure, the equilibrium condition is

Δ_{r} G^{\circ} = Δ_{r} H^{\circ} - T Δ_{r} S^{\circ} = 0

. Thus

T = \frac{141120}{170.7} = 826.71 K = 553.5 6^{\circ} C .

The calculation uses the stipulated constant reaction enthalpy and entropy, with the fluid at its reference chemical fugacity.

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