 Scaled subtraction of two spatially offset Raman spectra

Scaled subtraction of two spatially offset Raman spectra suppresses a common surface contribution by matching its amplitude between two measurements. The spatially offset Raman spectroscopy experiment establishes that collection offset can change surface and buried-layer proportions; numerical separation then needs a model of those contributions.^[ref] The following two-component subtraction is an original simplified case, not a claim that it reproduces the paper's full analysis.

Let fixed Raman spectra $S(\nu )$ and $B(\nu )$ describe the surface and buried material. Writewith $a_0\ne 0$. ThenIf the two mixing proportions are identical, so $a_0{b}_1-a_1{b}_0=0$, this cancels the buried component too. Offset diversity must supply different mixtures, not merely a weaker copy of the same spectrum.

For an original example, take $Y_0=10S+B$ and $Y_1=4S+3B$. The correct scale $k=0.40$ gives $Z=2.6B$. Using $k=0.42$ instead gives $Z=-0.2S+2.58B$: an incorrectly subtracted surface band can produce a negative residual even when both true spectra are nonnegative. A surface-specific reference band can estimate the scale only if the assumed common shape and response are adequate.

Noise remaining after scaled Raman subtraction is distinct from the cancelled mean signal. At a surface-only channel, suppose two independent acquisitions have Poisson photoelectron counts with means $10000$ and $4000$. For fixed $k=0.40$, the expected residual is zero, butgiving a standard deviation of about $74.8$ in the scaled count units. Subtraction has not erased shot noise. Correlated acquisitions and uncertainty in $k$ add further terms. Varying shape, wavelength-dependent attenuation or an unmatched fluorescence background can invalidate this simple linear separation.