 Steady Euler flow with vorticity proportional to its stream function

For a smooth planar incompressible flow, use $u={\psi }_y$, $v=-{\psi }_x$, so its scalar vorticity is $\omega =-\Delta \psi$. If $\omega =\lambda \psi$ for a constant $\lambda$, the flow solves the steady constant-density Euler equations with a suitable pressure.

Indeed the vector identity for the convective acceleration givesTherefore the pressure can be chosen so that the Bernoulli function satisfies $p/\rho +|\mathbf{u}{|}^2/2=C-\lambda {\psi }^2/2$. Its gradient is $-\omega \nabla \psi$, exactly the steady momentum equation. It is constant along each streamline, since the stream function is constant there.

For example $\psi =\sin x\cos y$ satisfies $\omega =2\psi$. Its pressure is $p_0-\rho {\sin }^{2}x/2+\rho {\sin }^{2}y/2$. Thus a rotational flow can have an explicit pressure and a streamline-dependent Bernoulli constant.