If such an existed, boundedness would make its isolated singularity at zero removable. Let be the holomorphic extension to the disc. Continuity gives . Equality at either endpoint contradicts the minimum-modulus principle applied to or the maximum modulus principle, since is nonconstant. Hence . Surjectivity of supplies some nonzero with , contradicting injectivity of the extension. Therefore
The closure is the intersection of all closed subsets containing ; equivalently, every neighbourhood of a point of meets . The subspace is dense when . A space is Hausdorff when distinct points have disjoint neighbourhoods.
For Hausdorff , the diagonal is closed in . Thus
is closed. Since it contains the dense set , it equals .
The conclusion fails without Hausdorffness. Let have the Sierpiński space topology and let , which is dense. The identity map and the constant map with value are continuous and agree on , but differ at .
A Hermitian form is conjugate-linear in its first argument, linear in its second, and satisfies . For , the hypothesis says . The complex polarization identity
therefore gives for all .
The displayed matrix is Hermitian. By Sylvester's criterion, its leading principal minors are
Hence the form is
Irrotationality gives and . At , the exact kinematic conditions are
and pressure continuity gives . Bernoulli equation in each fluid is
Linearize at and write . Decay at infinity gives
The kinematic conditions give , while pressure continuity gives
Elimination yields
Stable waves require the lower fluid to be denser, ; otherwise this is the Rayleigh-Taylor instability.

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