Past exam of the mathematics course of the University of Cambridge 2025 ii Paper 1 24G iii by
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Past exam of the mathematics course of the University of Cambridge 2025 ii Paper 1 21F Solution by
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The simplicial Mayer–Vietoris theorem says that if a simplicial complex for subcomplexes , there is a natural long exact sequenceThe reduced version extends through dimension zero.
For every simplex of , all faces of are either faces of or have the form with a face of , so they lie in . Each is a cone and hence a simplicial complex. For distinct , the rays in the last two coordinates through and are not positive multiples. Thus the two cones meet exactly in , so their simplices have common faces only in . Hence is a simplicial complex.
Topologically, is the union of three cones on along their common base. The first two cones form the suspension . Attaching the third contractible cone along the equatorial copy of givesThis also follows by applying reduced Mayer--Vietoris twice: every cone has zero reduced homology, and the two inclusion maps from the common base are null-homotopic inside the cones. Thereforefor every , with the convention that negative reduced homology vanishes. Since is nonempty, is connected, so explicitly
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