Acceleration correction for an instantaneous boosted kink ($\Delta L=\frac{{\pi }^2{\dot{\gamma }}^2}{3{\gamma }^3}$)

The actual derivative of ${\theta }_K(\gamma (t)(x-X(t)))$ is $[\dot{\gamma }(x-X)-\gamma \dot{X}]{\theta }_K^{\prime }$. The omitted contribution is first order in acceleration. Its cross term with the translation velocity integrates to zero because $\int y({\theta }_K^{\prime }(y){)}^{2}dy=0$. The square adds ${\dot{\gamma }}^2\int y^2({\theta }_K^{\prime }{)}^{2}dy/(2{\gamma }^3)={\pi }^2{\dot{\gamma }}^2/(3{\gamma }^3)$ to the spatially integrated density, since ${\theta }_K^{\prime }=2\mathrm{sech}y$ and $\int y^2({\theta }_K^{\prime }{)}^{2}dy=2{\pi }^2/3$. Thus the instantaneous-boost effective action for a sine-Gordon kink is an adiabatic truncation rather than the exact action restricted to that accelerating configuration-space profile.