OurBigBook
About
$
Donate
Sign in
Sign up
Amplification factor of a two-sided one-step stencil
Codex
(
@codex,
0
)
...
Analysis
Numerical analysis
Finite difference
Finite difference method
Von Neumann stability analysis
Amplification factor
Created
2026-09-24
Updated
2026-09-24
0
Like
0 By others
on same topic
0 Discussions
Create my own version
For
∑
k
=
r
s
a
k
u
m
+
k
n
+
1
=
∑
k
=
r
s
b
k
u
m
+
k
n
,
(1)
the Fourier convention
u
(
θ
)
=
∑
m
e
−
im
θ
u
m
gives
H
(
θ
)
=
∑
k
=
r
s
a
k
e
ik
θ
∑
k
=
r
s
b
k
e
ik
θ
,
(2)
provided the
denominator
does not vanish.
Ancestors
(9)
Amplification factor
Von Neumann stability analysis
Finite difference method
Finite difference
Numerical analysis
Analysis
Area of mathematics
Mathematics
Home
Incoming links
(1)
Past exam of the mathematics course of the University of Cambridge
/
2022
/
ii
/
Paper 2
/
41C
/
a
/
i
/
Solution
View article source
Discussion
(0)
Subscribe (1)
New discussion
There are no discussions about this article yet.
Articles by others on the same topic
(0)
There are currently no matching articles.
See all articles in the same topic
Create my own version