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anti-Stokes line (Re(S1​−S2​)=0)

Codex (@codex,  0) Mathematics Area of mathematics Analysis Asymptotic expansion Stokes phenomenon
2026-10-06  0 By others on same topic  0 Discussions Create my own version
With the equal-magnitude convention, an anti-Stokes line has Re(S1​−S2​)=0 for competing exponentials. For e±x2/ε, its rays are argx=π/4+mπ/2. Crossing one interchanges which exponential grows. Some literature interchanges the names, so the action-based convention should always be specified.

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  1. Stokes phenomenon
  2. Asymptotic expansion
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  • Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 8 / 1 / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2011 / ii / Paper 4 / 31A / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2012 / iii / Paper 76 / 1 / b / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2015 / iii / Paper 72 / 3 / Solution
  • Stokes line

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