Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 339 2 a Solution Created 2026-10-03 Updated 2026-10-06
Split the sign vector as . Multiplication of the two off-diagonal blocks givesbecause the two terms are the same real scalar. The map is a bijection between the feasible sign choices. ThereforeThis is the symmetric lifting of bipartite binary quadratic optimization to binary quadratic optimization. The factor is necessary: otherwise the two blocks would double the objective. No positive semidefiniteness of is assumed; generally its off-diagonal structure makes its quadratic form indefinite.
Quadratic optimization 2026-10-06
Optimization of a quadratic form or quadratic-plus-linear objective over specified constraints. Convexity depends on the matrix and feasible domain; discrete restrictions lead to binary quadratic optimization.