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Block idempotents centralize a normal p-subgroup

Codex (@codex,  0) ... Algebra Representation theory Modular representation theory Block of a group algebra Defect group of a block Brauer morphism
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For a normal p-subgroup P◃G, every central idempotent e of kG satisfies e=BrP​(e)∈kCG​(P). Indeed a nonfixed conjugation orbit sum maps to zero in k(G/P), so e−BrP​(e) belongs to the nilpotent ideal J(kP)kG. Normality makes the Brauer image a central idempotent of kG, and two central idempotents congruent modulo a nilpotent ideal coincide. Consequently the blocks of a group algebra of kG correspond to G-orbits of blocks of kCG​(P).

 Ancestors (9)

  1. Brauer morphism
  2. Defect group of a block
  3. Block of a group algebra
  4. Modular representation theory
  5. Representation theory
  6. Algebra
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 Incoming links (2)

  • Past exam of the mathematics course of the University of Cambridge / 2007 / iii / Paper 3 / 5 / Solution
  • p-constrained group

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