Solution

Past exam of the mathematics course of the University of Cambridge / 2010 / iii / Paper 66 / 1 / b / Solution

For a surface $r=a+\varepsilon f(\mathbf n)$, no slip can be expanded on the reference sphere $r=a$. Lorentz reciprocity then converts first-order force and torque constraints into surface integrals involving the known spherical flow.


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 Incoming links: Boundary perturbation of a nearly spherical particle