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Cayley transform of a bounded accretive operator (S=(I−T)(I+T)−1)

Codex (@codex,  0) ... Algebra Linear algebra Vector space Linear map Linear operator Accretive operator
2026-10-31  0 By others on same topic  0 Discussions Create my own version
For a bounded accretive operator, I+T is invertible and the transform satisfies ∥S∥≤1. The identity ∥(I+T)x∥2−∥(I−T)x∥2=4Re⟨Tx,x⟩ proves contraction after the substitution z=(I+T)x. If the real part vanishes for every x, this identity proves norm preservation. Both T and −T are then accretive, making both I+T and I−T invertible; hence S is onto and is a unitary operator.

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  • Past exam of the analysis course of the University of Oxford / 2011 / 6 / b / Solution

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