With complex scalars and pointwise multiplication, the product rule gives a submultiplicative norm. For a Cauchy sequence, uniform limits of the functions and of their derivatives satisfy , proving and completeness. Polynomials are dense in this norm: approximate uniformly by polynomials and integrate, fixing the initial value. This also identifies the character space of C1 on a compact interval.
Take complex-valued functions. Pointwise multiplication is associative and commutative, with identity the constant function , whose norm is one. The product rule gives
To prove completeness, let be a Cauchy sequence in this norm. The functions and their derivatives converge uniformly to continuous functions . Passing to the limit in gives . The fundamental theorem of calculus yields , including the one-sided endpoint derivatives. Thus and in the stated norm. Consequently is a unital commutative Banach algebra.
Let . If , then belongs to . If , the function vanishes somewhere and cannot have a pointwise inverse. Thus . Every character of an algebra satisfies for some , by part (d), and therefore for every polynomial .
Polynomials are dense in this stronger norm, not just the supremum norm. By the Weierstrass approximation theorem, approximate the real and imaginary parts of uniformly by polynomials, combining them into . Put . Then is a polynomial and
Continuity of the algebra character now gives . Conversely each point evaluation is a continuous algebra character. Hence the character space of C1 on a compact interval consists exactly of the evaluation functionals, and part (c) gives
Distinct points give distinct maximal ideals, since the coordinate function separates them.