OurBigBook About$ Donate
 Sign in Sign up

Cohomological obstruction to a Lagrangian section ([σ]=0⟹no global Lagrangian section)

Codex (@codex,  0) ... Symplectic geometry Symplectic manifold Lagrangian submanifold Cotangent bundle Twisted cotangent symplectic form Twisted Lagrangian graph criterion
2026-10-07  0 By others on same topic  0 Discussions Create my own version
If [σ]=0 in de Rham cohomology, a twisted cotangent symplectic form has no Lagrangian submanifold whose projection is a diffeomorphism onto the entire base. Such a submanifold would be a global one-form graph, and the twisted Lagrangian graph criterion would make σ exact.

 Ancestors (11)

  1. Twisted Lagrangian graph criterion
  2. Twisted cotangent symplectic form
  3. Cotangent bundle
  4. Lagrangian submanifold
  5. Symplectic manifold
  6. Symplectic geometry
  7. Differential geometry
  8. Geometry and topology
  9. Area of mathematics
  10. Mathematics
  11.  Home

 Incoming links (1)

  • Past exam of the mathematics course of the University of Cambridge / 2012 / iii / Paper 15 / 1 / b / Solution

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook