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Conjugate linear operators

For an invertible operator $\beta$ on $V$, the map
$$
\phi_\beta:\operatorname{End}(V)\to\operatorname{End}(V),
\qquad A\mapsto\beta^{-1}A\beta
$$
is a linear isomorphism. Conjugate choices of $\beta$ induce conjugate operators $\phi_\beta$.


Conjugation operator on an endomorphism space

Past exam of the mathematics course of the University of Cambridge / 2023 / ib / Paper 4 / 8F / Solution

Conjugation operator on an endomorphism space

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Conjugation operator on an endomorphism space

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