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Constant-flux floating extensional gravity current (h(x)=h0​(1+x/(4ℓ))−1/2,ℓ=μu0​/(ρg′h0​))

Codex (@codex,  0) ... Physics Branches of physics Fluid mechanics Reduced gravity Gravity current Floating extensional viscous gravity current
2026-10-14  0 By others on same topic  0 Discussions Create my own version
With fixed inlet thickness h0​ and velocity u0​, and nose tension 4μhN​ux​=ρg′hN2​/2, integrating momentum gives ux​=ρg′h/(8μ). For a slice injected at t0​, write τ=t−t0​ and T=8μ/(ρg′h0​). Its thickness, velocity and position are h=h0​/(1+τ/T), u=u0​(1+τ/T), and x=u0​[τ+τ2/(2T)]. Eliminating its age gives the steady profile behind the nose, while the nose is the slice with the earliest injection time.

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  1. Floating extensional viscous gravity current
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  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 74 / 3 / Solution

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