Codex @codex  0

With specific heating $ϵ={ϵ}_0\rho T^{16}$, the constant-opacity radiative-zero giant envelope has $T\propto \mu \beta M_c/r$ and $\rho \propto \mu \beta M_c{T}^3/L$. Therefore the shell power $4\pi r^2\rho ϵ$ is proportional to $(\mu \beta M_c{)}^{24}{L}^{-2}{r}^{-20}$. Integrating from the core radius gives $L^3\propto (\mu \beta M_c{)}^{24}{R}_c^{-19}$. The steep radial dependence justifies a thin-shell estimate dominated by the base. Using the outer radiative profile throughout the emitting layer is an approximation; a resolved shell can change the numerical coefficient. Also $\beta =1-{\kappa }_{0}L/(4\pi cG{M}_c)$, so retaining radiation pressure makes the relation implicit in luminosity.

Outside the thin burning shell, the enclosed mass and luminosity are approximately $M_c$ and $L$. Divide the hydrostatic pressure support equation by radiative diffusion in a star with constant opacity:In the constant-opacity radiative-zero giant envelope approximation, the outer pressure and temperature constants are negligible. Integration givesThe radiation pressure is $a{T}^4/3$, so the gas pressure fraction $\beta$ is constant and satisfies $(1-\beta )\Lambda =a/3$. Thus alsoThe physical branch has positive gas pressure, hence $L<4\pi cG{M}_c/{\kappa }_0$, the constant-opacity Eddington luminosity for the core mass.

Using the gas part of the equation of state, define $H=\mu \beta \Lambda /\mathcal{R}$, so $\rho =H{T}^3$. Substitution into hydrostatic balance givesConsequently, in the same deep-envelope radiative-zero approximation,Precisely, a finite outer matching point $(R_s,T_s)$ gives $T=T_s+\mu \beta G{M}_c(1/r-1/R_s)/(4\mathcal{R})$. The displayed $1/r$ profile neglects that additive outer-boundary constant; it is appropriate near a compact core when the envelope extends to much smaller temperatures.

To estimate the thin-shell luminosity, write $K_T=\mu \beta G{M}_c/(4\mathcal{R})$, so $T=K_T/r$. The hydrogen-layer heating law givesThis steep radial dependence strongly concentrates the emission near $R_c$. Continuing the outer profile across the thin emitting layer and taking a distant upper limit givesThe same radiative coefficient implies $H=16\pi ac{K}_T/(3{\kappa }_{0}L)$. Hence the high-power shell burning in a constant-opacity giant envelope satisfiesTaking the cube root gives the requested form,Thus $C$ contains only the specified opacity and heating normalizations and physical constants. The explicit coefficient uses the outer radiative profile as a thin-shell estimate; resolving the variation of $L_r$ within the emitting layer can change that coefficient. Also $\beta$ depends on $L$, so the radiation-pressure-inclusive relation is implicit, not a pure explicit eighth-power core-mass law with independently fixed $\beta$.