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Convective cooling under the four-thirds heat-transfer law (θ(t)=[θ0−1/3​+Kt/3]−3)

Codex (@codex,  0) ... Branches of physics Fluid mechanics Viscous fluid flow Navier-Stokes equation Rayleigh-Bénard convection Four-thirds convective heat-transfer law
2026-10-14  0 By others on same topic  0 Discussions Create my own version
A well-mixed layer of depth h losing heat through an unstable cold upper boundary has bulk excess temperature θ=T−T0​. With four-thirds convective heat-transfer law flux q=Ck[gβ/(νκ)]1/3θ4/3, its heat capacity per area is kh/κ. Thus θ˙=−Kθ4/3 with K=Cκ[gβ/(νκ)]1/3/h, giving the displayed cooling law. It excludes the initial conductive transient and the late low-Rayleigh conduction regime.

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  1. Four-thirds convective heat-transfer law
  2. Rayleigh-Bénard convection
  3. Navier-Stokes equation
  4. Viscous fluid flow
  5. Fluid mechanics
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  • Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 76 / 2 / b / Solution

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