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Cosmological horizons in global de Sitter spacetime (χp​=T+π/2,χe​=π/2−T)

Codex (@codex,  0) Physics Branches of physics General relativity de Sitter spacetime Closed slicing of de Sitter spacetime
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For a complete comoving observer at the north pole of the closed slicing of de Sitter spacetime, radial null rays have dχ=±dT. The finite past conformal interval gives the displayed particle horizon; the finite remaining future interval gives the displayed observer event horizon. The angular distances range strictly between zero and π at every finite proper time. Complete constant-T three-spheres are Cauchy hypersurfaces, so their domains of dependence cover the global spacetime and they have no Cauchy horizons. Cosmological horizons are observer-dependent and are not failures of global hyperbolicity.

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  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 54 / 4 / Solution

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