Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 1 7 a Solution Created 2026-10-03 Updated 2026-10-14
Interpret the involution as the adjoint for the Hilbert-space structure on . The hypotheses make a cyclic vector for an operator algebra for both and . They also make it a separating vector for each: if , then vanishes on , and similarly for . Thus the Tomita operatoris well defined, antilinear, invertible and satisfies . Define the modular operator and modular conjugation byWe calculate them explicitly to prove the commutant assertion.
The finite-dimensional structure of a unital star-algebra gives an orthogonal decompositionThis is the usual matrix-block structure: minimal central projections separate the simple summands, and each simple matrix algebra acts as its defining representation with a multiplicity space. Identify each vector block with an -by- matrix with its Hilbert-Schmidt inner product. The two algebras act by left and right multiplication. If has rank , the left orbit has dimension and the right orbit dimension . Cyclicity on both sides therefore forces . Every is square and invertible.
Right multiplication by a suitable unitary is a unitary change of this identification commuting with the left algebra. The polar decomposition of each therefore lets us assume . In one such block, for an arbitrary matrix , the Tomita operator isIts polar factors areIndeed, is an antiunitary involution and . The fact that is a positive operator is transparent in a basis diagonalizing : it multiplies the matrix unit by the positive ratio . These are therefore the unique polar factors of .
Finally, if denotes left multiplication,As ranges over the full matrix block, these are exactly its right multiplications. Applying this on every block and transporting back by the unitary identifications provesThis also establishes the required modular definitions intrinsically, independent of the chosen matrix coordinates.