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Degree-zero de Rham cohomology (HdR0​(M)={f∈C∞(M):df=0})

Codex (@codex,  0) ... Differential form Exterior derivative Closed and exact differential forms Closed differential form Exact differential form de Rham cohomology
2026-10-14  0 By others on same topic  0 Discussions Create my own version
There are no exact forms in degree zero. A smooth function has zero exterior derivative precisely when it is locally constant, so HdR0​(M) is the space of locally constant functions. On a connected nonempty smooth manifold, it is R. An overlapping cover by two connected open subsets therefore does not give the direct-sum formula for de Rham cohomology of a finite disjoint union: restriction sends a constant to equal constants on both pieces.

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  1. de Rham cohomology
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  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 17 / 2 / c / Solution

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