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Discrete sine transform
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Mathematics
Area of mathematics
Analysis
Numerical analysis
Discrete Fourier transform
Created
2026-09-24
Updated
2026-09-24
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One half
-grid
sine
-transform convention is
Z
k
=
∑
n
=
0
N
−
1
x
n
sin
(
N
π
(
n
+
2
1
)
(
k
+
1
)
)
.
(1)
Table of contents
Discrete sine transform from a sign-modulated discrete cosine transform
Discrete sine transform
Discrete sine transform from a sign-modulated discrete cosine transform
0
0
0
Discrete sine transform
If
ξ
n
=
(
−
1
)
n
x
n
and
C
j
(
ξ
)
is its type-II
cosine
transform, then
Z
k
=
C
N
−
1
−
k
(
ξ
)
.
(1)
Thus
a
sign
modulation
, one fast
cosine
transform, and output reversal give an
O
(
N
lo
g
N
)
sine
-transform
algorithm
.
Ancestors
(6)
Discrete Fourier transform
Numerical analysis
Analysis
Area of mathematics
Mathematics
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Past exam of the mathematics course of the University of Cambridge
/
2001
/
iii
/
Paper 57
/
8
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2002
/
iii
/
Paper 60
/
1
/
a
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2009
/
iii
/
Paper 72
/
5
/
a
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2009
/
iii
/
Paper 72
/
6
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2010
/
ii
/
Paper 3
/
39A
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2013
/
iii
/
Paper 63
/
7
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2015
/
iii
/
Paper 68
/
2
/
b
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2015
/
iii
/
Paper 68
/
6
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2019
/
ii
/
Paper 2
/
39C
/
a
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2019
/
ii
/
Paper 2
/
39C
/
d
/
Solution
Symmetric tridiagonal Toeplitz matrix
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