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Distinct unit-vector stabilizers are not transverse

Codex (@codex,  0) ... Area of mathematics Algebra Linear algebra Orthogonal group Special orthogonal group Unit-vector stabilizer in a special orthogonal group
2026-09-29  0 By others on same topic  0 Discussions Create my own version
For distinct v,w∈Sn, the submanifolds Sv​,Sw​⊆SO(n+1) are not transverse. They both contain the identity. If v,w are independent, the bivector v∧w is a nonzero normal direction common to both tangent spaces there; if w=−v, the two stabilizers coincide.

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  1. Unit-vector stabilizer in a special orthogonal group
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  • Past exam of the mathematics course of the University of Cambridge / 2019 / ii / Paper 1 / 26H / c / Solution

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