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The tangent modulus is the local slope of a specified uniaxial stress-strain curve:It converts a small additional strain near ${\epsilon }_0$ into the corresponding first-order change of stress. For nonlinear elastic deformation, this slope can vary with the operating point.^[ref] In uniaxial linear elasticity, $\sigma =E\epsilon$, so the tangent modulus equals the constant Young's modulus.^[ref]

For an original nonlinear branch, stipulateThen $E_{\tan }=E_0+2B\epsilon$. At ${\epsilon }_0=0.02$, the stress is $80\mathrm{MPa}$ and the tangent modulus is $6\mathrm{GPa}$. The secant modulus from the stipulated unloaded origin is instead $\sigma /{\epsilon }_0=4\mathrm{GPa}$. The two slopes answer different questions: the secant compares total stress and strain, while the tangent predicts a small further increment.

For $\Delta \epsilon =0.001$, the tangent predicts $\Delta \sigma \simeq 6\mathrm{MPa}$. The exact change in the chosen polynomial is $6.1\mathrm{MPa}$ because the omitted term is $B(\Delta \epsilon {)}^2=0.1\mathrm{MPa}$. This is a linear approximation whose error decreases quadratically with the increment, not a claim that the nonlinear material obeys Hooke's law globally.

To estimate a tangent modulus experimentally, specify the stress and strain measures, temperature, loading history and loading rate. For engineering stress $\sigma =F/A_0$ and engineering strain $\epsilon =\Delta L_g/L_g$ from a local extensometer,Fit a local window about the chosen operating point and check how the estimate changes with that window. For an original $L_g=50\mathrm{mm}$, $A_0=10\mathrm{m}{\mathrm{m}}^2$ and local slope $1200\mathrm{N}\mathrm{m}{\mathrm{m}}^{-1}$, this gives $6000\mathrm{N}\mathrm{m}{\mathrm{m}}^{-2}=6\mathrm{GPa}$. Differentiation amplifies measurement noise, and crosshead displacement can include machine compliance. Where plastic deformation or history-dependent response occurs, identify the loading branch: its local slope need not equal the unloading slope or an elastic material constant.