Equal-amplitude states of an eight-mode square pattern

For the four wavevectors $(2,1),(2,-1),(1,2),(1,-2)$ and their negatives, use invariant phases ${\chi }_1=2{\theta }_1-2{\theta }_2-{\theta }_3+{\theta }_4$, ${\chi }_2={\theta }_1+{\theta }_2-2{\theta }_3-2{\theta }_4$. Add to the cubic normal form of a dynamical system the two quintic terms $e{\overline{A}}_2{A}_3^2{A}_4^2$ and $f{\overline{A}}_1{A}_2^2{A}_3{\overline{A}}_4$ in the first equation, together with their square-symmetry partners; $e,f$ are real. For equal positive magnitudes, steadiness forces $\sin {\chi }_1=\sin {\chi }_2=0$ unless $e=f=0$. Equality of radial equations further gives $(e-f)(\cos {\chi }_1-\cos {\chi }_2)=0$. Consequently the generic phase types are $(0,0)$ and $(\pi ,\pi )$. When $e=f\ne 0$, the mixed type $(0,\pi )$, equivalent by square symmetry to $(\pi ,0)$, also exists. When both quintic coefficients vanish, every phase pair is allowed. Amplitude existence must still be checked from the remaining scalar equation.