Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 23 1 a Solution Created 2026-10-03 Updated 2026-10-14
Let be a finite diagram. Form the finite categorical productsThere are two morphisms : their components at are and , respectively. Let be their equaliser. Then satisfy , so they constitute a cone over a diagram.
Any other cone uniquely determines . Its cone equations say precisely that . The equaliser therefore gives a unique with , and thus . Conversely these component equations force by the categorical product universal property, so there is exactly one such mediator. This proves that is a categorical limit of .
The empty categorical products are included: if is empty, and are terminal and the construction gives the empty categorical limit. Thus finite categorical products and equalisers give every finite categorical limit, as a special case of the construction of small limits from products and equalizers.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 23 1 b Solution Created 2026-10-03 Updated 2026-10-14
Let be a terminal object. The pullback of the unique arrows is a binary categorical product: maps and automatically have equal composites into , so the pullback universal property is exactly the categorical product universal property.
For parallel arrows , form and take the pullback of along the diagonal . Write the resulting projections as and . The pullback equation givesIf satisfies , the pair is a pullback cone, producing a unique with and . The second condition is forced by the first, since . Thus is the equaliser of .
The terminal object and iterated binary categorical products give all finite categorical products, including the nullary one. Part (a) therefore proves pullbacks and a terminal object give all finite categorical limits.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 23 2 b Solution Created 2026-10-03 Updated 2026-10-14
Write an object of the slice category as . Its morphisms are arrows in commuting with these structure maps, and the forgetful functor removes the structure map.
Suppose a square in the slice becomes a pullback square in , with vertex . Given a compatible pair of slice arrows and , the underlying pullback gives a unique with the required projection equations. If is one projection, thenwhere is the structure map. Thus is automatically a slice morphism, and underlying uniqueness gives uniqueness in the slice. Hence reflects pullbacks.
Now let be an equaliser of slice arrows . Consider any underlying arrow with . Give the structure map . Then is a slice arrow into , and the slice equaliser gives a unique with . Conversely any underlying with that equation automatically obeys , so there are no additional factorization possibilities outside the slice. Therefore has the ordinary equaliser universal property in . This proves preserves equalisers.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 23 2 c Solution Created 2026-10-03 Updated 2026-10-14
Let be the unique arrow to the terminal object of . DefineThis is a functor into the slice category , because , and . The terminal object of this slice is , exactly , so preserves the terminal object.
The composite preserves pullbacks by hypothesis, and reflects pullbacks by part (b). Part (a), restricted to the pullback shape, therefore shows that preserves pullbacks. The allowed finite-limit criterion now gives that preserves all finite categorical limits, and hence equalisers. Since preserves equalisers, their composite does too. ThusThis is equalizer preservation by pullback-preserving functors. The factorization supplies terminal-object preservation only in the slice; none is asserted for the original .
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 23 4 c Solution Created 2026-10-03 Updated 2026-10-14
By part (b), is the equaliser of and . Full faithfulness of the Yoneda embedding writes for a unique endomorphism . Choose an equaliser of and in .
For each , the maps are precisely the maps with . Thus is the pointwise equaliser of and , hence their equaliser in the presheaf category. Both and have the same universal property, so their vertices are isomorphic. This proves the representable retract criterion:
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 23 4 e Solution Created 2026-10-03 Updated 2026-10-14
By the canonical colimit presentation of a presheaf, writewith structure maps . Since is a 0-presentable object, the canonical mapis bijective. Every element of a set-valued colimit has a representative in some component. In particular is the image of a transformation for some , soThus is a retract of . The representable retract criterion from part (c), using the assumed equalisers in , now gives is representable. Only existence of the representative of is needed; no stronger uniqueness-of-factorization assertion about individual colimit injections has been assumed.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 23 6 Solution Created 2026-10-03 Updated 2026-10-14
The Freyd general adjoint functor theorem is as follows. Let , with a complete category which is locally small. Then has a left adjoint if and only if it preserves all small categorical limits and satisfies the solution-set condition: for each , there is a set-indexed familysuch that every can be written for some and some . The target category need not be complete. We prove all the existence steps.
First establish the initial-object lemma for complete categories with a weakly initial set. Let be locally small and complete, with a weakly initial set , meaning every object receives a map from at least one . Its categorical product is weakly initial: compose a categorical product projection with the map from the appropriate . Local smallness makes a set. Let be the simultaneous equaliser of every endomorphism of and the identity. Explicitly it is the equaliser of the two arrowswith components and . Thus for every endomorphism , and is monic.
Every object receives a morphism from , by composing with a map . To prove uniqueness, take parallel maps and their equaliser . Weak initiality of gives . The composite is an endomorphism of , so . Cancelling the monomorphism gives . Hence is both monic and a split epimorphism, and is therefore invertible. Since , this forces . We have proved is initial, without using a class-sized categorical product or equaliser.
For sufficiency in the theorem, fix and consider the comma category . Its objects are pairs ; a morphism satisfies . This category is locally small because each hom-set is a subset of . It is complete: for a small diagram of such pairs, take the underlying categorical limit in . The arrows from form a cone to its image under , and preservation of the categorical limit gives a unique inducing them. The same universal property gives all mediators in the comma category. The solution-set family is a weakly initial set in this comma category, so the lemma supplies an initial pairFor , initiality defines a unique satisfying . Uniqueness proves the identity and composition laws, making a functor. Initiality also gives bijectionsThe definition of proves naturality in , and postcomposition proves naturality in . These bijections are the required adjunction .
For necessity, if , the single arrow is a solution set: the transpose of any gives its factorization through . If is a limiting cone vertex of a small diagram in , then, naturally in ,These are the canonical cone-factorization bijections, so with its image projections is a categorical limit of . Thus preserves all small categorical limits, completing both directions of the theorem.