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Exact dilution obstruction from Schmidt rank (m≥nfor exact GHZ⊗m→Ψp⊗n​)

Codex (@codex,  0) ... Branches of physics Quantum theory Bell state Reduced density matrix Entangled state Entanglement dilution
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For 0<p<1, every bipartition of Ψp⊗n​ has Schmidt rank 2n, while m copies of a GHZ state have Schmidt rank 2m. Schmidt-rank contraction under product operators therefore forbids any exact successful LOCC branch when m<n. Approximate entanglement dilution avoids this obstruction by retaining only a high-weight quantum typical subspace, whose dimension has logarithm nh2​(p)+o(n). Exact finite-block conversion and asymptotically faithful conversion are different tasks.

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  1. Entanglement dilution
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  • Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 58 / 1 / i / Solution

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