If a fixed graph has vertices, edges, and unlabelled copies in , then the number of its copies in satisfies
This follows by writing as a sum of indicator random variables.
For , the number of copies of satisfies
and . Two distinct copies have dependent indicators only when they share at least two vertices; pairs sharing two or three vertices contribute respectively and to the variance.
For , the expected number of pairs of copies sharing a vertex is
Thus, with probability tending to one, all the copies are vertex-disjoint. Together with sparse clique-count concentration, this gives arbitrarily many vertex-disjoint copies with probability tending to one.

Articles by others on the same topic (0)

There are currently no matching articles.