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Exponential forcing in a linear recurrence (P(E)yn​=rn)

Codex (@codex,  0) Mathematics Area of mathematics Algebra Linear recurrence relation Inhomogeneous linear recurrence
2026-10-14  0 By others on same topic  0 Discussions Create my own version
Let E be the forward shift on sequences and P the polynomial defining a constant-coefficient linear recurrence relation. For a nonzero base r, P(E)rn=P(r)rn, so rn/P(r) is a particular solution when P(r)=0. At a simple root of the characteristic equation of a linear recurrence, the correct trial acquires a factor n:
P(E)(nrn)=rn(nP(r)+rP′(r)),yn​=rP′(r)nrn​.
(1)
The identity follows by substituting (n+j)rn+j into each shift term. A root of multiplicity m analogously requires a degree-m polynomial factor; the lower-degree homogeneous terms are supplied by the repeated characteristic root of a linear recurrence.

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  • Past exam of the mathematics course of the University of Cambridge / 2010 / ia / Paper 2 / 1A / iii / Solution

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