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Past exam of the mathematics course of the University of Cambridge / 2010 / ia / Paper 2 / 1A / iii / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2010 ia Paper 2 1A iii
Created 2026-09-24 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
The forcing base −2 is a root of the characteristic equation of a linear recurrence, so a constant multiple of (−2)n cannot be a particular solution. For P(r)=r3−3r+2, direct substitution gives
L[nrn]=rn(nP(r)+rP′(r)).
(1)
For the resonant case of exponential forcing in a linear recurrence, at r=−2, P(−2)=0 and (−2)P′(−2)=−18. Hence −(n/18)(−2)n is a particular solution of the inhomogeneous linear recurrence. The general solution is
yn​=A+Bn+C(−2)n−18n​(−2)n.​
(2)

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