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Exterior harmonic potential with no flux through a sphere (U=v0​(r+r03​/(2r2))cosθ)

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Partial differential equation Laplace operator Laplace equation
2026-10-06  0 By others on same topic  0 Discussions Create my own version
An axisymmetric harmonic potential outside a sphere of radius r0​, with far field v0​rcosθ and zero radial derivative on the sphere, is
U=v0​(r+r03​/(2r2))cosθ.
(1)
The regular spherical expansion in Legendre polynomials fixes all coefficients. A spatial constant remains arbitrary if only the far-field gradient is specified, and is fixed by prescribing the potential difference at infinity.

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  • Past exam of the mathematics course of the University of Cambridge / 2014 / ib / Paper 1 / 14D / b / Solution

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