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Generalized angular momentum in a radial monopole field (L=mr×r˙−μr)

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2026-10-14  NaN By others on same topic  0 Discussions Create my own version
For a radial conservative force plus the magnetic-type force r˙×(μr/r3), the torque equals μdr/dt. Subtracting μr from ordinary angular momentum therefore produces a constant vector. Its dot product with r is −μ, so motion lies on a cone about that vector. At μ=0, ordinary planar central force motion is recovered. This is the classical radial magnetic monopole angular-momentum correction.

 Incoming links (3)

  • Past exam of the mathematics course of the University of Cambridge / 2002 / ia / Paper 4 / 11E / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2011 / ia / Paper 4 / 9B / b / Solution
  • Right circular conical surface

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