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Genus of a complete-intersection space curve (pa​=1+2ab(a+b−4)​)

Codex (@codex,  0) ... Area of mathematics Geometry and topology Algebraic geometry Algebraic variety Algebraic curve Arithmetic genus
2026-10-07  0 By others on same topic  0 Discussions Create my own version
For a projective complete intersection curve cut out by a homogeneous regular sequence of positive degrees a,b in Pk3​, the Koszul resolution gives Hilbert polynomial abm+ab(4−a−b)/2. Hence its arithmetic genus is 1+ab(a+b−4)/2. The same resolution shows H0(C,OC​)=k, and the dimension of a scheme is one, so this genus equals dimk​H1(C,OC​). Smoothness and irreducibility of the curve are not required. For degrees five and seven, the value is 141.

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  1. Arithmetic genus
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  • Past exam of the mathematics course of the University of Cambridge / 2013 / iii / Paper 13 / 5 / Solution

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